Do all of the Ardbox units have the 5V dc output rated to 1.5A?
If this supply is used to drive a display (for example) does this limit the availability of any of the serial coms options (232 / 485 / SPI / I2C)?
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Do all of the Ardbox units have the 5V dc output rated to 1.5A?
If this supply is used to drive a display (for example) does this limit the availability of any of the serial coms options (232 / 485 / SPI / I2C)?
Hello Duncan,
No, you can use the pin 5V without losing any serial coms option, to get more info about the serial coms you can have a look to the user guide so you can see the configuration that you need to do to work of any of them ( RS - 485, RS - 232, SPI, I2C). Also i can show you an example of using I2C connecting an LiquidCrystal LCD and also the code of it.
#include <Wire.h>
#include <LiquidCrystal_I2C.h>
#if defined(ARDUINO) && ARDUINO >= 100
#define printByte(args) write(args);
#else
#define printByte(args) print(args,BYTE);
#endif
uint8_t bell[8] = {0x4,0xe,0xe,0xe,0x1f,0x0,0x4};
uint8_t note[8] = {0x2,0x3,0x2,0xe,0x1e,0xc,0x0};
uint8_t clock[8] = {0x0,0xe,0x15,0x17,0x11,0xe,0x0};
uint8_t heart[8] = {0x0,0xa,0x1f,0x1f,0xe,0x4,0x0};
uint8_t duck[8] = {0x0,0xc,0x1d,0xf,0xf,0x6,0x0};
uint8_t check[8] = {0x0,0x1,0x3,0x16,0x1c,0x8,0x0};
uint8_t cross[8] = {0x0,0x1b,0xe,0x4,0xe,0x1b,0x0};
uint8_t retarrow[8] = { 0x1,0x1,0x5,0x9,0x1f,0x8,0x4};
LiquidCrystal_I2C lcd(0x27,20,4); // set the LCD address to 0x27 for a 16 chars and 2 line display
void setup()
{
lcd.init(); // initialize the lcd
lcd.backlight();
lcd.createChar(0, bell);
lcd.createChar(1, note);
lcd.createChar(2, clock);
lcd.createChar(3, heart);
lcd.createChar(4, duck);
lcd.createChar(5, check);
lcd.createChar(6, cross);
lcd.createChar(7, retarrow);
lcd.home();
lcd.printByte(3);
lcd.print(" INDUSTRIAL ");
lcd.printByte(3);
lcd.setCursor(0, 1);
//lcd.print(" i ");
lcd.printByte(3);
lcd.print(" SHIELDS ");
lcd.printByte(3);
delay(10000);
displayKeyCodes();
}
// display all keycodes
void displayKeyCodes(void) {
uint8_t i = 0;
while (1) {
lcd.clear();
lcd.print("Codes 0x"); lcd.print(i, HEX);
lcd.print("-0x"); lcd.print(i+16, HEX);
lcd.setCursor(0, 1);
for (int j=0; j<16; j++) {
lcd.printByte(i+j);
}
i+=16;
delay(4000);
}
}
void loop()
{
}
Thank you,
Best regards.
how did you know the 5VDC output was rated to 1.5A? Where is the documentation that states this? Thank you